16x^2-85x+50=0

Solution for 16x^2-85x+50=0 equation:

16x^2-85x+50=0

a = 16; b = -85; c = +50;
Δ = b2-4ac
Δ = -852-4·16·50
Δ = 4025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4025}=\sqrt{25*161}=\sqrt{25}*\sqrt{161}=5\sqrt{161}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-85)-5\sqrt{161}}{2*16}=\frac{85-5\sqrt{161}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-85)+5\sqrt{161}}{2*16}=\frac{85+5\sqrt{161}}{32}
$